The circuit contains two diodes each with a forward resistance of 50 and with infinite reverse resistance. If the battery voltage is 6 V, the current through the 120 resistance is---------mA.
<p>D<sub>1</sub> is forward biased & D<sub>2 </sub>is reverse biased.</p><p><math><mrow><mi>l</mi><mo>=</mo><mfrac><mrow><mn>6</mn></mrow><mrow><mn>1</mn><mn>2</mn><mn>0</mn><mo>+</mo><mn>1</mn><mn>3</mn><mn>0</mn><mo>+</mo><mn>5</mn><mn>0</mn></mrow></mfrac><mo>=</mo><mfrac><mrow><mn>6</mn></mrow><mrow><mn>3</mn><mn>0</mn><mn>0</mn></mrow></mfrac><mo>=</mo><mn>2</mn><mo>×</mo><mn>1</mn><msup><mrow><mn>0</mn></mrow><mrow><mo>−</mo><mn>2</mn></mrow></msup><mi>A</mi><mo>=</mo><mn>2</mn><mn>0</mn><mo>×</mo><mn>1</mn><msup><mrow><mn>0</mn></mrow><mrow><mo>−</mo><mn>3</mn></mrow></msup><mi>A</mi><mo>=</mo><mn>2</mn><mn>0</mn><mi>m</mi><mi>A</mi></mrow></math></p>
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