The circuit shown in the figure is in steady state for a long time. The connection to battery is suddenly broken (switch S is opened up). What is the charge (in
) on the capacitor after 0.001 sec.?
The circuit shown in the figure is in steady state for a long time. The connection to battery is suddenly broken (switch S is opened up). What is the charge (in ) on the capacitor after 0.001 sec.?
Option 1 -
100
Option 2 -
100 e-2
Option 3 -
100 e‑4
Option 4 -
0
-
1 Answer
-
Correct Option - 3
Detailed Solution:p.d across capacitor = 20 v
Q = CV = 5 * 20 = 100
After S is open
Q = Q . e-t/RC
=100 e-4
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