The container shown in Fig. has two chambers, separated by a partition, of volumes V1 = 2.0 litre and V2= 3.0 litre. The chambers contain µ1 = 4.0and µ2 =5.2 moles of a gas at pressures p1= 1.00 atm and p2 = 2.00 atm. Calculate the pressure after the partition is removed and the mixture attains equilibrium.


The container shown in Fig. has two chambers, separated by a partition, of volumes V1 = 2.0 litre and V2= 3.0 litre. The chambers contain µ1 = 4.0and µ2 =5.2 moles of a gas at pressures p1= 1.00 atm and p2 = 2.00 atm. Calculate the pressure after the partition is removed and the mixture attains equilibrium.


This is a short answer type question as classified in NCERT Exemplar
V1=2L ,V2=3L
µ1 = 4.0and µ2 =5.2
p1= 1.00 atm and p2 = 2.00 atm
p1V1= µ1RT1
p2V2= µ2RT2
when the partition is removed the gases get mixed without any loss of energy . the mixture now attains a common equilibrium pressure and total volume
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physics ncert solutions class 11th 2023
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