The current in a coil of self inductance 2.0 H is increasing according to I = 2sin(t2)A. The amount of energy spent during the period when current changes from 0 to 2 A is…………J.

Given, L = 2Hl = 2 sin (t2) u = ∫ 0 2 L i d i = L 2 [ i 2 ] 0 2 = L 2 [ 4 − 0 ] u = 2 2 × 4 = 4 J

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Electromagnetic Induction Physics Ncert Solutions Class 12th Physics Class 12th

The current in a coil of self inductance 2.0 H is increasing according to I = 2sin(t²)A. The amount of energy spent during the period when current changes from 0 to 2 A is…………J.

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Payal Gupta | Contributor-Level 10

2 months ago

Given, L = 2H

l = 2 sin (t²)

$u = \int_{0}^{2} L i d i = \frac{L}{2} {[i^{2}]}_{0}^{2} = \frac{L}{2} [4 - 0]$

$u = \frac{2}{2} \times 4 = 4 J$

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The current in a coil of self inductance 2.0 H is increasing according to I = 2sin(t²)A. The amount of energy spent during the period when current changes from 0 to 2 A is…………J.

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