The de Broglie wavelength associated with an electron and a proton were calculated by accelerating them through same potential of 100V. What should be the ratio of their wavelengths? (m? = 1.00727u, m? = 0.00055u)
The de Broglie wavelength associated with an electron and a proton were calculated by accelerating them through same potential of 100V. What should be the ratio of their wavelengths? (m? = 1.00727u, m? = 0.00055u)
Option 1 -
43 : 1
Option 2 -
41.4 : 1
Option 3 -
41.4 : 1
Option 4 -
1860 : 1
Asked by Shiksha User
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1 Answer
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Correct Option - 1
Detailed Solution:Using de-Broglie equation:
λ = h/p = h/√ (2mK) = h/√ (2meV)
λ ∝ 1/√m
λ? /λ? = √ (m? /m? ) = √ (1.00727/0.00055) = √1831 ≈ 43:1
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