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The electric field in a region is given by E⃗ = (2/5)E₀ î + (3/5)E₀ ĵ with E₀ = 4.0 × 10³ N/C. The flux of this field through a rectangular surface area 0.4m² parallel to the Y-Z plane is _____ Nm²C⁻¹.

0 5 Views | Posted a month ago
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    Answered by

    alok kumar singh | Contributor-Level 10

    a month ago

    The flux φ is calculated as:
    φ = (2/5) * 4 * 10³ * 0.4 = 640 Nm²C? ¹

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