Physics Ncert Solutions Class 12th Semiconductor Electronics: Materials, Devices and Class 12th Physics

The electron concentration in an n-type semiconductor is the same as hole concentration in a p-type semiconductor. An external field (electric) is applied across each of them. Compare the currents in them.

Option 1 - <p>Current in n-type = current in p-type.</p>

Option 2 - <p>Current in p-type <span class="mathml" contenteditable="false"> <math> <mn>10.2</mn> <mtext> </mtext> <mi mathvariant="normal">k</mi> <mi mathvariant="normal">W</mi> </math> </span> current in n-type.</p>

Option 3 - <p>Current in n-type <span class="mathml" contenteditable="false"> <math> <mn>8.1</mn> <mtext> </mtext> <mi mathvariant="normal">k</mi> <mi mathvariant="normal">W</mi> </math> </span>current in p-type.</p>

Option 4 - <p>No current will flow in p-type, current will only flow in n-type.</p>

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Answered by

Alok Kumar Singh | Contributor-Level 10

5 months ago

Correct Option - 3

Detailed Solution:

In n-type semiconductor majority charge carriers are e- and P type semiconductor majority charge carriers are holes.

$I = {n e A V}_{d} =$ neA $(μ E)$

$μ_{e} > μ_{h} \Rightarrow I_{e} > I_{h}$

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Physics Ncert Solutions Class 12th 2023

Physics Ncert Solutions Class 12th 2023

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