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The escape velocity of a body on a planet ‘A’ is 12 kms-1. The escape velocity of the body on another planet ‘B’, whose density is four times and radius is half of the planet ‘A’, is:

Option 1 -

12 kms-1

Option 2 -

24 kms-1

Option 3 -

36 kms-1

Option 4 -

6 km-1

0 2 Views | Posted 2 months ago
Asked by Shiksha User

  • 1 Answer

  • A

    Answered by

    alok kumar singh | Contributor-Level 10

    2 months ago
    Correct Option - 1


    Detailed Solution:

    M A = ρ A × 4 3 π R A 3 ρ B = 4 ρ A

    M B = ρ B × 4 3 π R B 3 R B = R A 2

    M A M B = 2 , R A R B = 2 V E A V E B = 2 G 1 M A R A × R B 2 G 1 M B

    v E A = v E B = 1 2 k m     s e c − 1

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