The function of time representing a simple harmonic motion with time period of π/ω is:
The function of time representing a simple harmonic motion with time period of π/ω is:
Option 1 -
sin(ωt) + cos(ωt)
Option 2 -
sin²(ωt)
Option 3 -
3cos(π/4 - 2ωt)
Option 4 -
cos(ωt) + cos(2ωt) + cos(3ωt)
Asked by Shiksha User
-
1 Answer
-
Correct Option - 3
Detailed Solution:(A) sin (ωt) + cos (ωt) = √2 sin (ωt + π/4) ⇒ T = 2π/ω
(B) sin² (ωt) = 1/2 - (1/2)cos (2ωt) ⇒ T = 2π/ (2ω) = π/ω
(C) 3cos (π/4 - 2ωt) ⇒ T = 2π/ (2ω) = π/ω
(D) cos (ωt) + cos (2ωt) + cos (3ωt)
Time period of cos (ωt) = 2π/ω
Time period of cos (2ωt) = 2π/ (2ω)
Time period of cos (3ωt) = 2π/ (3ω)
Time period of combined function = 2π/ω
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 65k Colleges
- 1.2k Exams
- 688k Reviews
- 1800k Answers