The function of time representing a simple harmonic motion with time period of π/ω is:
The function of time representing a simple harmonic motion with time period of π/ω is:
Option 1 - <p>sin(ωt) + cos(ωt)<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 2 - <p>sin²(ωt)<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 3 - <p>3cos(π/4 - 2ωt)<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 4 - <p>cos(ωt) + cos(2ωt) + cos(3ωt)</p>
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5 months ago
Correct Option - 3
Detailed Solution:
(A) sin (ωt) + cos (ωt) = √2 sin (ωt + π/4) ⇒ T = 2π/ω
(B) sin² (ωt) = 1/2 - (1/2)cos (2ωt) ⇒ T = 2π/ (2ω) = π/ω
(C) 3cos (π/4 - 2ωt) ⇒ T = 2π/ (2ω) = π/ω
(D) cos (ωt) + cos (2ωt) + cos (3ωt)
Time period of cos (ωt) = 2π/ω
Time period of cos (2ωt) = 2π/ (2ω)
Time period of cos (3ωt) = 2π/ (3ω)
Time per
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Physics Oscillations 2025
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