The given potentiometer has its wire of resistance 10Ω. When the sliding contact is in the middle of the potentiometer wire, the potential drop across 2Ω resistor is :
Applying nodal analysis at point X with potential xV: (x-20)/5 + (x-0)/2 + (x-20)/5 = 0 2 (x-20) + 5x + 2 (x-20) = 0 9x - 80 = 0 => x = 80/9 V Potential drop across 2Ω resistor = x = 80/9 V. (Note: There seems to be a discrepancy in the provided solution and standard circuit analysis. The provided solu
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