The half-life of a radioactive nuclide is 100 hours. The fraction of original activity that will remain after 150 hours would be: &lt;!-- [if !supportLineBreakNewLine]--&gt; &lt;!--[endif]--&gt;

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Physics Nuclei Physics Class 12th Nuclei

The half-life of a radioactive nuclide is 100 hours. The fraction of original activity that will remain after 150 hours would be:

Option 1 -

$\frac{1}{2}$

Option 2 -

$\frac{1}{2 \sqrt[]{2}}$

Option 3 -

$\frac{2}{3}$

Option 4 -

$\frac{2}{3 \sqrt[]{2}}$

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Asked by Shiksha User

1 Answer

Answered by

alok kumar singh | Contributor-Level 10

2 months ago

Correct Option - 2

Detailed Solution:

$\frac{A}{A_{0}} = {(\frac{1}{2})}^{t / T_{H}} = {(\frac{1}{2})}^{150 / 100} = \frac{1}{2 \sqrt[]{2}}$

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The half-life of a radioactive nuclide is 100 hours. The fraction of original activity that will remain after 150 hours would be:

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