The image of an object placed in air formed by a convex refracting surface is at a distance of 10 m behind the surface. The image is real and is at 2/3 of the distance of the object from the surface. The wavelength of light inside the surface is 2/3 times the wavelength in air. The radius of the curved surface is x/13 m. The value of 'x' is _____.

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    Answered by

    alok kumar singh | Contributor-Level 10

    a month ago

    Given the refractive index μ = λ? / λ = 3/2 and v = 10m, the object distance is u = - (3/2)v = -15m.
    Using the lens maker's formula:
    μ/v - 1/u = (μ - 1)/R
    (3/2)/10 - 1/ (-15) = (3/2 - 1)/R
    This gives the radius of curvature R:
    R = -30/13 m

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