The magnitude and direction of the current in the following circuit is
The magnitude and direction of the current in the following circuit is
Option 1 - <p>. 1.5 A from B A through<span class="mathml" contenteditable="false"> <math> <mi mathvariant="normal">E</mi> </math> </span><!--[endif]--><!--[endif]--><br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 2 - <p>. 0.2 A from <span class="mathml" contenteditable="false"> <math> <mi>B</mi> </math> </span> to <span class="mathml" contenteditable="false"> <math> <mi>A</mi> </math> </span>through <span class="mathml" contenteditable="false"> <math> <mi>E</mi> </math> </span><!--[endif]--><!--[endif]--></p>
Option 3 - <p>0.5 A from A to B through <span class="mathml" contenteditable="false"> <math> <mi mathvariant="normal">E</mi> </math> </span><br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 4 - <p><span class="mathml" contenteditable="false"> <math> <mfrac> <mrow> <mrow> <mn>5</mn> </mrow> </mrow> <mrow> <mrow> <mn>9</mn> </mrow> </mrow> </mfrac> <mtext> </mtext> <mi mathvariant="normal">A</mi> </math> </span>from <span class="mathml" contenteditable="false"> <math> <mi mathvariant="normal">A</mi> </math> </span> to <span class="mathml" contenteditable="false"> <math> <mi mathvariant="normal">B</mi> </math> </span>through <span class="mathml" contenteditable="false"> <math> <mi mathvariant="normal">E</mi> </math> </span><!--[endif]--><!--[endif]--></p>
2 Views|Posted 5 months ago
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1 Answer
A
Answered by
5 months ago
Correct Option - 4
Detailed Solution:
First band
Red
2nd band Red
3rd band =Orange (Multiplier)
4th band = Gold (Tolerance)
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Physics Current Electricity 2025
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