The motion of a particle of mass m is given by x = 0 for t < 0 s, x(t) = A sin4 t for 0 < t<(1/4)s(A>0) and x = 0 for t >(1/4) s. Which of the following statements is true?

(a) The force at t = (1/8) s on the particle is –16π2 A m.

(b) The particle is acted upon by on impulse of magnitude 4π2 A m at t = 0 s and t = (1/4) s.

(c) The particle is not acted upon by any force.

(d) The particle is not acted upon by a constant force.

(e) There is no impulse acting on the particle.

2 Views|Posted 6 months ago
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6 months ago

This is a Multiple Choice Questions type Questions as classified in NCERT Exemplar

Answer- a, b, d

Explanation – x=0 for t<0s

X (t)=Asin4 π t  for 0

X=0, for t>1/4s

For,0 π t

Acceleration will be, a= dv/dt=-16 π 2 Asin4 π t

At t= 1/8 s, a (t)=-16 π 2 Asin4 π 1 8 =-16 π 2 A

So force F =ma =-16 π 2 Am

Impulse = change in linear momentu

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Physics NCERT Exemplar Solutions Class 11th Chapter Five 2025

Physics NCERT Exemplar Solutions Class 11th Chapter Five 2025

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