The new white belt of a long horizontal conveyor is moving with a constant speed v = 3.0m/s. A small block of carbon is placed on the belt with zero initial velocity relative to the ground. The block will slip a bit before moving with the belt, leaving a black mark on the belt (figure). How long is that mark (in m) if the coefficient of kinetic friction between the carbon block and the belt is 0.20 and the coefficient of static friction is 0.30?

3 Views | Posted 3 weeks ago

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Answered by

Vishal Baghel | Contributor-Level 10

3 weeks ago

$0^{2} = v^{2} - 2 μ_{k} g S_{r e l}$

$\frac{9}{2 \times 2} = S_{r e l} = 2.25 m$

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