The new white belt of a long horizontal conveyor is moving with a constant speed v = 3.0m/s. A small block of carbon is placed on the belt with zero initial velocity relative to the ground. The block will slip a bit before moving with the belt, leaving a black mark on the belt (figure). How long is that mark (in m) if the coefficient of kinetic friction between the carbon block and the belt is 0.20 and the coefficient of static friction is 0.30?

67 Views|Posted 5 months ago
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1 Answer
V
5 months ago

0 2 = v 2 2 μ k g S r e l

9 2 * 2 = S r e l = 2 . 2 5 m

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Physics Laws of Motion 2025

Physics Laws of Motion 2025

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