The number of significant figures in 0.06900 is
(a) 5
(b) 4
(c) 2
(d) 3
The number of significant figures in 0.06900 is
(a) 5
(b) 4
(c) 2
(d) 3
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1 Answer
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This is a multiple choice answer as classified in NCERT Exemplar
(b) The zero after points are not significant. The number can be written as 0.069, Hence number of significant figure are four.
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According to question, we can write
Total moles of gas = n = nOxygen + nOxygen =
Volume of gas = 12 × 22.4 litre = 268.8 litre = 2.688 × 105 cm3
Viscosity = Pascal . Second
=
= x = 1, x + 2y = -1, -x + z = 1
y = -1, Z = 0
Viscosity = [P1A-1T0]
1 msD = 1mm
10 vsD = 9msD
1vsD = 0.9 MsD
L.C. = 1MSD – 1VSD = 1 – 0.9 = 0.1 mm
Zero error = 4LC = 0.4 mm
Reading = MSR + VSR + correction
= 4.1 cm + 6 * .01 cm + (-0.04 cm) = (4.1 + 0.06 – 0.04) cm
= 4.12 cm = 412 * 10-2 cm
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