The relation between time t and distance x for a moving body is given as t = mx² + nx, where m and n are constants. The retardation of the motion is: (Where v stands for velocity)

Option 1 - <p>2n²v³</p>
Option 2 - <p>2mnv³</p>
Option 3 - <p>2mv³</p>
Option 4 - <p>2nv³</p>
10 Views|Posted 5 months ago
Asked by Shiksha User
1 Answer
A
5 months ago
Correct Option - 3
Detailed Solution:

By t = mx² + nx
dt/dx = 2mx + n
V = dx/dt = 1/ (2mx + n)
a = v (dv/dx) = V (d/dx (1/ (2mx+n) = V [-2m/ (2mx+n)²] = -2mV³
So, Retardation will be (2mv³)

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Physics Motion in Straight Line 2025

Physics Motion in Straight Line 2025

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