The time period of satellite in a circular orbit of radius R is T. The period of another satellite in a circular orbit of radius 9R is: &lt;!-- [if !supportLineBreakNewLine]--&gt; &lt;!--[endif]--&gt;

27 T

12 T

9 T

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Keplers Law Physics Gravitation Physics Class 11th

The time period of satellite in a circular orbit of radius R is T. The period of another satellite in a circular orbit of radius 9R is:

Option 1 -

12 T

Option 2 -

9 T

Option 3 -

27 T

Option 4 -

3 T

2 Views | Posted a month ago

Asked by Shiksha User

1 Answer

Answered by

Raj Pandey | Contributor-Level 9

a month ago

Correct Option - 3

Detailed Solution:

T² ∝ R³
⇒ (T? /T? )² = (R? /R? )³ ⇒ T? = 9³/² T = 27T

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Raj Pandey

According to kepler’s third law of time period –

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A satellite is launched into a circular orbit of radius R around earth, while a second satellite is launched into a circular orbit of radius 1.02R. The percentage difference in the time periods of the two satellites is:

Vishal Baghel

Time period of Satellite = T = $\frac{2 π R}{v} = {(\frac{4 π^{2} R^{3}}{G M})}^{\frac{1}{2}}$

$\Rightarrow T α R^{\frac{3}{2}} \Rightarrow \frac{T_{2}}{T_{1}} = \frac{{(1.02 R)}^{\frac{3}{2}}}{R^{\frac{3}{2}}} = {(1.02)}^{\frac{3}{2}} = {(1 + 0.02)}^{\frac{3}{2}}$

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