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Two planets A and B of equal mass are having their period of revolutions TA and TB such that TA = 2TB. These planets are revolving in the circular orbits or radii rA and rB respectively. Which out of the following would be the correct relationship of their orbits?

Option 1 -

2 r A 2 = r B 3

Option 2 -

r A 3 = 2 r B 3

Option 3 -

r A 3 = 4 r B 3

Option 4 -

T A 2 − T B 2 = π 2 G M ( r B 3 − 4 r A 3 )

0 2 Views | Posted 2 weeks ago
Asked by Shiksha User

  • 1 Answer

  • R

    Answered by

    Raj Pandey | Contributor-Level 9

    2 weeks ago
    Correct Option - 3


    Detailed Solution:

    According to kepler’s third law of time period –

      ( T A T B ) 2 = ( r A r B ) 3 ⇒ r A r B = 4 1 / 3  

    ⇒ r 4 3 = 4 r B 3  

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