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The value of the acceleration due to gravity is g₁ at a height h = R/2 (R = radius of the earth) from the surface of the earth. It is again equal to g₁ at a depth d below the surface of the earth. The ratio (d/R) equals:

Option 1 -

7/9

Option 2 -

1/3

Option 3 -

5/9

Option 4 -

4/9

0 4 Views | Posted 2 months ago
Asked by Shiksha User

  • 1 Answer

  • A

    Answered by

    alok kumar singh | Contributor-Level 10

    2 months ago
    Correct Option - 3


    Detailed Solution:

    dW? = Eqdx
    ∫ dU? = ∫ kQ/x² dxq
    W? = kQq (-1/x)|? ^ (R+y)
    W? = kQq (y)/ (R) (R + y)
    W? + W? = 1/2 mv²
    V² = 2/m (kQqy/ (R) (R+y) + mgy)
    V² = 2y (kQq/ (m (R) (R+y) + g) ; k = 1/ (4πε? )

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