Three copper blocks of masses M1, M2 and M3 kg respectively are brought into thermal contact till they reach equilibrium. Before contact, they were at T1, T2, T3 (T1 > T2 > T3 ). Assuming there is no heat loss to the surroundings, the equilibrium temperature T is (s is specific heat of copper)

(a) T= T 1 + T 2 + T 3 3

(b) T= M 1 T 1 + M 2 T 2 + M 3 T 3 M 1 + M 2 + M 3  

(c)  T= M 1 T 1 + M 2 T 2 + M 3 T 3 3 ( M 1 + M 2 + M 3 )

(d) T= M 1 T 1 s + M 2 T 2 s + M 3 T 3 s M 1 + M 2 + M 3   

3 Views|Posted 7 months ago
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1 Answer
P
7 months ago

This is a multiple choice answer as classified in NCERT Exemplar

(b) Let us assume that T1, T2T3

According to questions there is no loss of heat in the surroundings

Heat lost by M3 = heat gained by M1+ heat gained by M2

M3s (T3-T)= M1s (T-T1)+M2s (T-T2)

T [M1+M2+M3]= M3T3+M1T1+M2T2

T = M 1 T 1 + M 2 T 2 + M 3 T 3 M 1 + M 2 + M 3

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physics ncert solutions class 11th 2023

physics ncert solutions class 11th 2023

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