Three masses M = 100kg, m1 = 10kg and M2 = 20kg are arranged in a system as shown in figure. All the surface are frictionless and strings are inextensible and weightless. The pulleys are also weightless and frictionless. A force F is applied on the system so that the mass m2 moves upward with an acceleration of 2ms-2. The value of F is:
(Take g = 10ms-2)
Three masses M = 100kg, m1 = 10kg and M2 = 20kg are arranged in a system as shown in figure. All the surface are frictionless and strings are inextensible and weightless. The pulleys are also weightless and frictionless. A force F is applied on the system so that the mass m2 moves upward with an acceleration of 2ms-2. The value of F is:
(Take g = 10ms-2)
Given Acceleration of m2 is 2m/s2
(upward)
N = 20a T – m2g = m2a
T – 20g = 20a
T = 200 + 20 * 2
T = 240 N
T = m1 a1
240 = 10a1
a1 = 24 m/s2
F – T – N = Ma2
F – 240 = 100 * 26 + 20 * 26
F = 3360 N
Similar Questions for you
T1 = m (g + a)
T2 = m (g - a)
Apparent weight = mg – ma
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