Three masses M = 100kg, m1 = 10kg and M2 = 20kg are arranged in a system as shown in figure. All the surface are frictionless and strings are inextensible and weightless. The pulleys are also weightless and frictionless. A force F is applied on the system so that the mass m2 moves upward with an acceleration of 2ms-2. The value of F is:

(Take g = 10ms-2)

Option 1 - <p>3360 N</p>
Option 2 - <p>3380 N</p>
Option 3 - <p>3120 N</p>
Option 4 - <p>3240 N</p>
745 Views|Posted 7 months ago
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1 Answer
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7 months ago
Correct Option - 1
Detailed Solution:

Given Acceleration of m2 is 2m/s2

(upward)

N = 20a              T – m2g = m2a

T – 20g = 20a

T = 200 + 20 * 2

T = 240 N

T = m1 a1

240 = 10a1

a1 = 24 m/s2

Ta+Ta1Ta2=0

a2=24+2=26m/s2

F – T – N = Ma2

F – 240 = 100 * 26 + 20 * 26

F = 3360 N

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