Three rods of identical cross-section and lengths are made of three different materials of thermal conductivity K₁, K₂, and K₃, respectively. They are joined together at their ends to make a long rod (see figure). One end of the long rod is maintained at 100°C and the other at 0°C (see figure). If the joints of the rod are at 70°C and 20°C in steady state and there is no loss of energy from the surface of the rod, the correct relationship between K₁, K₂ and K₃ is:
In steady state rate of flow of heat in all three rods are same. dQ/dt = (k? A (100 – 70)/? = (k? A (70 – 20)/? = (k? A (20 – 0)/? 30k? = 50k? = 20k? ∴ k? : k? = 2:3 & k? : k? = 2:5
<p>In steady state rate of flow of heat in all three rods are same.<br>dQ/dt = (k? A (100 – 70)/? = (k? A (70 – 20)/? = (k? A (20 – 0)/? <br><!- [if !supportLineBreakNewLine]-><!- [endif]->30k? = 50k? = 20k? <br>∴ k? : k? = 2:3 & k? : k? = 2:5</p>
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