Three rods of identical cross-section and lengths are made of three different materials of thermal conductivity K₁, K₂, and K₃, respectively. They are joined together at their ends to make a long rod (see figure). One end of the long rod is maintained at 100°C and the other at 0°C (see figure). If the joints of the rod are at 70°C and 20°C in steady state and there is no loss of energy from the surface of the rod, the correct relationship between K₁, K₂ and K₃ is:

 

Option 1 - <p>K₁: K₃ = 2:3, K₂: K₃ = 2:5<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 2 - <p>K₁ &lt; K₂ &lt; K₃</p>
Option 3 - <p>K₁: K₂ = 5:2, K₁: K₃ = 3:5</p>
Option 4 - <p>K₁ &gt; K₂ &gt; K₃<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
11 Views|Posted 5 months ago
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5 months ago
Correct Option - 1
Detailed Solution:

In steady state rate of flow of heat in all three rods are same.
dQ/dt = (k? A (100 – 70)/? = (k? A (70 – 20)/? = (k? A (20 – 0)/?
30k? = 50k? = 20k?
∴ k? : k? = 2:3 & k? : k? = 2:5

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Physics Thermal Properties of Matter 2025

Physics Thermal Properties of Matter 2025

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