Three students S1, S2 and S2 perform an experiment for determining the acceleration due to gravity (g) using a simple pendulum. They use different lengths of pendulum and record time for different number of oscillations. The observations are as shown in the table.

Student

No.

Length of Pendulum (cm)

No. of oscillations (n)

Total for n oscillations

Time period (s)

1

64.0

8

128.0

16.0

2

64.0

4

64.0

16.0

3

20.0

4

36.0

9.0

Least count of length = 0.1 cm

least count for time = 0.1 s)

If E1, E2 and E3 are the percentage errors ‘g’ for students 1, 2 and 3 respectively, then the minimum percentage error is obtained by student no.___________.

0 4 Views | Posted a month ago
Asked by Shiksha User

  • 1 Answer

  • V

    Answered by

    Vishal Baghel | Contributor-Level 10

    a month ago

    T = 2 π l g

    g = 4 π 2 l T 2

    Δ g g = Δ l l + 2 Δ T T

    Student 1 will get least error because it has more number of oscillation

Get authentic answers from experts, students and alumni that you won't find anywhere else

Sign Up on Shiksha

On Shiksha, get access to

  • 65k Colleges
  • 1.2k Exams
  • 688k Reviews
  • 1800k Answers

Learn more about...

Share Your College Life Experience

Didn't find the answer you were looking for?

Search from Shiksha's 1 lakh+ Topics

or

Ask Current Students, Alumni & our Experts

×
×

This website uses Cookies and related technologies for the site to function correctly and securely, improve & personalise your browsing experience, analyse traffic, and support our marketing efforts and serve the Core Purpose. By continuing to browse the site, you agree to Privacy Policy and Cookie Policy.

Need guidance on career and education? Ask our experts

Characters 0/140

The Answer must contain atleast 20 characters.

Add more details

Characters 0/300

The Answer must contain atleast 20 characters.

Keep it short & simple. Type complete word. Avoid abusive language. Next

Your Question

Edit

Add relevant tags to get quick responses. Cancel Post