Time for 20 oscillations of a pendulum is measured as t1= 39.6 s; t 2= 39.9 s; t 3= 39.5 s. What is the precision in the measurements? What is the accuracy of the measurement?
Time for 20 oscillations of a pendulum is measured as t1= 39.6 s; t 2= 39.9 s; t 3= 39.5 s. What is the precision in the measurements? What is the accuracy of the measurement?
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1 Answer
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This is a short answer type question as classified in NCERT Exemplar
t1=39.6s, t2=39.9s and t3=39.5s
Least count of measuring instrument =0.1s
Precision in the measurement =least count of the measuring instrument =0.1s
So mean value of 20 observation
Mean value of t=
Absolute error in
t1= t-t1 = 39.7-39.6 =0.1s
In t2= t-t2 = 39.7-39.9=-0.2s
In t3= t-t1 = 39.7-39.5= 0.2s
Mean error =
Accuracy in the measurement =
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Total moles of gas = n = nOxygen + nOxygen =
Volume of gas = 12 × 22.4 litre = 268.8 litre = 2.688 × 105 cm3
Viscosity = Pascal . Second
=
= x = 1, x + 2y = -1, -x + z = 1
y = -1, Z = 0
Viscosity = [P1A-1T0]
1 msD = 1mm
10 vsD = 9msD
1vsD = 0.9 MsD
L.C. = 1MSD – 1VSD = 1 – 0.9 = 0.1 mm
Zero error = 4LC = 0.4 mm
Reading = MSR + VSR + correction
= 4.1 cm + 6 * .01 cm + (-0.04 cm) = (4.1 + 0.06 – 0.04) cm
= 4.12 cm = 412 * 10-2 cm
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