Train A and train B are running on parallel tracks in opposite directions with speed of 36 km/hour and 72 km/hour, respectively. A person is walking in train A in the direction opposite to its motion with a speed of 1.8 km/hour. Speed (in ms⁻¹) of this person as observed from train B will be close to: (take the distance between the tracks as negligible)

Option 1 - <p>28.5 ms⁻¹</p>
Option 2 - <p>31.5 ms⁻¹</p>
Option 3 - <p>30.5 ms⁻¹<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 4 - <p>29.5 ms⁻¹</p>
6 Views|Posted 5 months ago
Asked by Shiksha User
1 Answer
A
5 months ago
Correct Option - 4
Detailed Solution:

V? = 36 km/hr = 10 m/s
V? = -72 km/hr = -20 m/s
V? = -1.8 km/hr = -0.5 m/s

V? = V? + V?

= V? + V? - V?
= -0.5 + 10 – (-20)
= -0.5 + 30 = 29.5 m/s

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Physics Motion in Straight Line 2025

Physics Motion in Straight Line 2025

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