Two billiard balls of mass 0.05 kg each moving in opposite directions with 10ms-1 collide and rebound with the same. If the time duration of contact is t = 0.005s. Then what is the force exerted on the ball due to each other?

Option 1 - <p>100N</p>
Option 2 - <p>200N</p>
Option 3 - <p>300N</p>
Option 4 - <p>400N</p>
6 Views|Posted 8 months ago
Asked by Shiksha User
1 Answer
P
8 months ago
Correct Option - 2
Detailed Solution:

Δp = Change in momentum of each ball

Δp=2mv=2*0.05*10=1Ns

F=ΔpΔt=2*0.05*100.005=200N

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