Two blocks of masses 3kg and 5kg are connected by a metal wire going over a smooth pulley. The breaking stress of the metal is $\frac{24}{π} \times 1 0^{2} N m^{- 2} .$ What is the minimum radius of the wire? (take g = 10ms^-2)

Option 1 -

1250cm

Option 2 -

125cm

Option 3 -

12.5cm

Option 4 -

1.25cm

2 Views | Posted 3 weeks ago

Asked by Shiksha User

1 Answer

Answered by

Vishal Baghel | Contributor-Level 10

3 weeks ago

Correct Option - 3

Detailed Solution:

Tension in wire, $T = \frac{2 \times 3 \times 5 \times 10}{3 + 5} = \frac{75}{2} N$

$\frac{T}{π r_{m i n}^{2}} = \frac{24}{π} \times 1 0^{2}$

$\Rightarrow r_{m i n}^{2} = \frac{75}{2 \times 24} \times 1 0^{- 2} = \frac{25}{16} \times 1 0^{- 2}$
$\Rightarrow r_{m i n} = \frac{5}{4} \times 1 0^{- 1} m = 12.5 c m$

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Two blocks of masses 3kg and 5kg are connected by a metal wire going over a smooth pulley. The breaking stress of the metal is $\frac{24}{π} \times 1 0^{2} N m^{- 2} .$ What is the minimum radius of the wire? (take g = 10ms^-2)

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Two blocks of masses 3kg and 5kg are connected by a metal wire going over a smooth pulley. The breaking stress of the metal is 2 4 π × 1 0 2 N m − 2 . What is the minimum radius of the wire? (take g = 10ms-2)

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Two blocks of masses 3kg and 5kg are connected by a metal wire going over a smooth pulley. The breaking stress of the metal is $\frac{24}{π} \times 1 0^{2} N m^{- 2} .$ What is the minimum radius of the wire? (take g = 10ms^-2)