Two capacitros are fully charged by a battery as shown in the figure.

If the capacitors are disconnected from battery and plate 1 is connected to plate 4 & plate 2 to plate 3, then find the potential difference (in volts) across capacitors finally.

0 2 Views | Posted 3 weeks ago
Asked by Shiksha User

  • 1 Answer

  • V

    Answered by

    Vishal Baghel | Contributor-Level 10

    3 weeks ago

    Charge initially on capacitor 1=10µC
    Charge initially on capacitor 2=20µC
    Finally the potential difference across both capacitor will be equal.
    Let us assume that to be V.
    1V + 2V = +10
    V = 10 / 3 = 3.33V

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