Two cells of same emf but different internal resistance r₁ and r₂ are connected in series with a resistance R. The value of resistance R, for which the potential difference across second cell is zero, if:

Option 1 - <math> <mrow> <msub> <mrow> <mi>r</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msub> <mo>−</mo> <msub> <mrow> <mi>r</mi> </mrow> <mrow> <mn>1</mn> </mrow> </msub> </mrow> </math>

Option 2 - r1 – r2

Option 3 - r1

Option 4 - r2

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Answered by

Raj Pandey | Contributor-Level 9

6 months ago

Correct Option - 1

Detailed Solution:

Given

$I = \frac{2 E}{R = r_{1} + r_{2}}$

E₁ = E₂ = E - (i)

Potential drop across second cell is

$V_{A} - E_{2} + I r_{2} = v_{B}$

According to question VA – VB = 0

E2 lr2 = 0

$\Rightarrow R = r_{2} - r_{1}$

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Two cells of same emf but different internal resistance r1 and r2 are connected in series with a resistance R. The value of resistance R, for which the potential difference across second cell is zero, if:

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