Two different wires having lengths and , and respective temperature coefficient of linear 4expansion and , are joined end-to-end. Then the effective temperature coefficient of linear expansion is:
Two different wires having lengths and , and respective temperature coefficient of linear 4expansion and , are joined end-to-end. Then the effective temperature coefficient of linear expansion is:
At T°C L = L? + L?
At T +? T Leq = L'? + L'?
where L'? = L? (1 + α? T)
L'? = L? (1 + α? T)
Leq = (L? + L? ) (1 + αavg? T)
⇒ (L? + L? ) (1 + αavg? T) = L? + L? + L? α? T + L? α? T
⇒ (L? + L? )αavg = L? α? + L? α?
⇒ αavg = (L? α? + L? α? )/ (L? + L? )
Similar Questions for you
Thermal stress is developed on heating when expansion of rod is hindered.
According to question, we can write
400 × 1 × 12.5 = 500 × 5 × (100 – 36.5)
S = 10 cal/mol °C
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else.
On Shiksha, get access to
Learn more about...

Physics Thermal Properties of Matter 2025
View Exam DetailsMost viewed information
SummaryDidn't find the answer you were looking for?
Search from Shiksha's 1 lakh+ Topics
Ask Current Students, Alumni & our Experts
Have a question related to your career & education?
See what others like you are asking & answering
