Two identical charged particles each having a mass 10g and charge 2.0 × 10^-7 C are placed on a horizontal table with a separation of L between them such that they stay in limited equilibrium. If the coefficient of friction between each particle and the table is 0.25, find the value of L. [Use g = 10ms^-2]

Option 1 -

12 cm

Option 2 -

10 cm

Option 3 -

8 cm

Option 4 -

5 cm

4 Views | Posted 3 months ago

Asked by Shiksha User

1 Answer

Answered by

Payal Gupta | Contributor-Level 10

3 months ago

Correct Option - 1

Detailed Solution:

$μ m g = \frac{k q_{1} q_{2}}{L^{2}}$

$\Rightarrow 0.25 \times 0.01 \times 10 = \frac{9 \times 1 0^{9} \times 2 \times 1 0^{- 7} \times 2 \times 1 0^{- 7}}{L^{2}}$

$= \frac{9 \times 2^{2} \times 1 0^{- 5 + 4}}{25 \times 10}$

L = 12 cm

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