Two identical charged particles each having a mass 10g and charge 2.0 * 10-7 C are placed on a horizontal table with a separation of L between them such that they stay in limited equilibrium. If the coefficient of friction between each particle and the table is 0.25, find the value of L. [Use g = 10ms-2]

Option 1 - <p>12 cm&nbsp; &nbsp; &nbsp;&nbsp;</p>
Option 2 - <p>10 cm&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</p>
Option 3 - <p>8 cm&nbsp;</p>
Option 4 - <p>5 cm</p>
14 Views|Posted 6 months ago
Asked by Shiksha User
1 Answer
P
6 months ago
Correct Option - 1
Detailed Solution:

μmg=kq1q2L2

0.25*0.01*10=9*109*2*107*2*107L2

=9*22*105+425*10

L = 12 cm

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Physics Electrostatic Potential and Capacitance 2025

Physics Electrostatic Potential and Capacitance 2025

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