Two identical cylindrical vessels are kept on the ground and each contain the same liquid of density d. The area of the base of both vessels is S but the height of liquid in one vessel is x1 and in the other, x2. When both cylinders are connected through a pipe of negligible volume very close to the bottom, the liquid flows from one vessel to the other until it comes to equilibrium at a new height. The change in energy of the system in the process is :

Option 1 - <p>1/4 gdS(x₂ − x₁)²<br>&lt;!-- [if !supportLineBreakNewLine]--&gt;<br>&lt;!--[endif]--&gt;</p>
Option 2 - <p>gdS(x₂ + x₁)²<br>&lt;!-- [if !supportLineBreakNewLine]--&gt;<br>&lt;!--[endif]--&gt;</p>
Option 3 - <p>1/2 gdS(x₂ − x₁)²<br>&lt;!-- [if !supportLineBreakNewLine]--&gt;<br>&lt;!--[endif]--&gt;<br>&lt;!--[endif]--&gt;</p>
Option 4 - <p>gdS(x₂² + x₁²)/2<br>&lt;!-- [if !supportLineBreakNewLine]--&gt;<br>&lt;!--[endif]--&gt;</p>
5 Views|Posted 5 months ago
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1 Answer
V
5 months ago
Correct Option - 3
Detailed Solution:

sx? dg (x? /2) + sx? dg (x? /2)
Uf = (S (x? +x? )/2)gd (x? +x? )/4) x 2
= S (x? + x? )²gd/4
U? -Uf = (Sgd/4) {2x? ² + 2x? ² − (x? + x? )²}
= (Sgd/4) (x? -x? )²

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Physics Mechanical Properties of Fluids 2025

Physics Mechanical Properties of Fluids 2025

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