Two ions of masses 4 amu and 16 amu have charges +2e and +3e respectively. These ions pass through the region of constant perpendicular magnetic field. The kinetic energy of both ions is same. Then:

Option 1 - No ion will be deflected.

Option 2 - Both ions will be deflected equally

Option 3 - Lighter ion will be deflected more than heavier ion

Option 4 - Lighter ion will be deflected less than heavier ion

4 Views|Posted 4 months ago

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Answered by

Vishal Baghel | Contributor-Level 10

4 months ago

Correct Option - 3

Detailed Solution:

$R = \frac{\sqrt[]{2 E m}}{B . q}$

$\Rightarrow R * \frac{\sqrt[]{m}}{q}$

$\Rightarrow \frac{R_{1}}{R_{2}} = \frac{\sqrt[]{4}}{2} * \frac{3}{\sqrt[]{16}} = \frac{3}{4}$

$\Rightarrow R_{2} = \frac{4 R_{1}}{3}$

$s i n θ = \frac{d}{R} \Rightarrow θ α \frac{1}{2} \Rightarrow θ_{2} < θ_{1}$

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Physics Moving Charges and Magnetism 2025

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