Two mercury droplets of radii 0.1 cm. and 0.2 cm. collapse into one single drop. What amount of energy is released? The surface tension of mercury T= 435.5 * 10-3 Nm-1 .

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8 months ago

This is a short answer type question as classified in NCERT Exemplar

Consider the diagram

Radii of mercury droplets  r1=0.1cm = 1 * 10 - 3 m

r2=0.2cm=2 * 10 - 3 m

Surface tension T= 435.5 * 10-3 Nm-1

Let the radius of the big drop formed by collapsing be R

Therefore,

volume of big drop = volume of small droplets

4/3 π R3=4/3

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Physics NCERT Exemplar Solutions Class 11th Chapter Ten 2025

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