Two sources of sound emitting sound of nearly equal wavelengths λ₁ and λ₂ are fixed at A and B respectively. A listener moves with velocity u on the perpendicular bisector of line joining A and B. Then the number of beats heard by him per second when it is at distance 2l from A and B, is (Speed of sound = C)
Two sources of sound emitting sound of nearly equal wavelengths λ₁ and λ₂ are fixed at A and B respectively. A listener moves with velocity u on the perpendicular bisector of line joining A and B. Then the number of beats heard by him per second when it is at distance 2l from A and B, is (Speed of sound = C)
Option 1 - <p>(C - (u√3)/2) (1/λ₁ - 1/λ₂)<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 2 - <p>((2C-u)/2) (1/λ₁ - 1/λ₂)<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 3 - <p>(C - √3u) (1/λ₁ - 1/λ₂)<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 4 - <p>Zero</p>
9 Views|Posted 5 months ago
Asked by Shiksha User
1 Answer
V
Answered by
5 months ago
Correct Option - 1
Detailed Solution:
θ = 60?
f? = (C - u (√3/2)/λ?
f? = (C - u (√3/2)/λ?
|f? - f? | = | (C - u (√3/2) (1/λ? - 1/λ? )|
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