Two spherical soap bubbles of radii r₁ and r₂ in vacuum combine under isothermal conditions. The resulting bubble has radius equal to :

Option 1 - <p>√r₁r₂</p>
Option 2 - <p>√r₁² + r₂²</p>
Option 3 - <p>(r₁r₂)/(r₁ + r₂)</p>
Option 4 - <p>(r₁ + r₂)/2</p>
3 Views|Posted 6 months ago
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1 Answer
A
6 months ago
Correct Option - 2
Detailed Solution:

Pressure outside is 0.
Here, Pin = 4T/r
By, P? V? + P? V? = PV (isothermal process, Boyle's law applied to the mass of gas inside)
(4T/r? ) (4/3 πr? ³) + (4T/r? ) (4/3 πr? ³) = (4T/r) (4/3 πr³)
r? ² + r? ² = r²
r = √r? ² + r? ²

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Physics Mechanical Properties of Fluids 2025

Physics Mechanical Properties of Fluids 2025

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