Two spherical soap bubbles of radii r₁ and r₂ in vacuum combine under isothermal conditions. The resulting bubble has radius equal to :
Two spherical soap bubbles of radii r₁ and r₂ in vacuum combine under isothermal conditions. The resulting bubble has radius equal to :
Option 1 -
√r₁r₂
Option 2 -
√r₁² + r₂²
Option 3 -
(r₁r₂)/(r₁ + r₂)
Option 4 -
(r₁ + r₂)/2
Asked by Shiksha User
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1 Answer
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Correct Option - 2
Detailed Solution:Pressure outside is 0.
Here, Pin = 4T/r
By, P? V? + P? V? = PV (isothermal process, Boyle's law applied to the mass of gas inside)
(4T/r? ) (4/3 πr? ³) + (4T/r? ) (4/3 πr? ³) = (4T/r) (4/3 πr³)
r? ² + r? ² = r²
r = √r? ² + r? ²
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