Two springs with spring constants  k 1 = 1200 N / m and k 2 = 500 N / m  are stretched by the same force. The ratio of potential energy in the springs will be

Option 1 - <p><span class="mathml" contenteditable="false"> <math> <mfrac> <mrow> <mrow> <mn>25</mn> </mrow> </mrow> <mrow> <mrow> <mn>144</mn> </mrow> </mrow> </mfrac> </math> </span></p>
Option 2 - <p><span class="mathml" contenteditable="false"> <math> <mfrac> <mrow> <mrow> <mn>12</mn> </mrow> </mrow> <mrow> <mrow> <mn>5</mn> </mrow> </mrow> </mfrac> </math> </span></p>
Option 3 - <p><span class="mathml" contenteditable="false"> <math> <mfrac> <mrow> <mrow> <mn>5</mn> </mrow> </mrow> <mrow> <mrow> <mn>10</mn> </mrow> </mrow> </mfrac> </math> </span></p>
Option 4 - <p><span class="mathml" contenteditable="false"> <math> <mfrac> <mrow> <mrow> <mn>144</mn> </mrow> </mrow> <mrow> <mrow> <mn>25</mn> </mrow> </mrow> </mfrac> </math> </span></p>
3 Views|Posted 4 months ago
Asked by Shiksha User
1 Answer
A
4 months ago
Correct Option - 3
Detailed Solution:

Elastic potential energy stored in the spring

U = 1 2 k x 2

= 1 2 F x = F 2 2 k

H e n c e U 1 U 2 = k 2 k 1 F i s s a m e f o r b o t h s p r i n g s

= 500 1200 = 5 12

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Physics NCERT Exemplar Solutions Class 11th Chapter Eight 2025

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