We would like to prepare a scale whose length does not change with temperature. It is proposed to prepare a unit scale of this type whose length remains, say 10 cm. We can use a bimetallic strip made of brass and iron each of different length whose length (both components) would change in such a way that difference between their lengths remain constant. If 5 αiron =1.2 * 10-5/K and αbrass 1.8 * 10-5 /K , what should we take as length of each strip?

2 Views|Posted 8 months ago
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8 months ago

This is a long answer type question as classified in NCERT Exemplar

As liron-lbrass =10cm= constant at all temperature

Let lo be the length of temperature at 00C  and l be the length after change in temperature

liron-lbrass =10cm

liron (1+ α i r o n ? t )-lbrass (1+ α b r a s s ? t )=10cm

Iiron α iron= Ibrass α brass

l i r o n l b r a s s =1.8/1.2=3/2

1 2 l b r a s s = 10 c m

L

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Physics NCERT Exemplar Solutions Class 11th Chapter Eleven 2025

Physics NCERT Exemplar Solutions Class 11th Chapter Eleven 2025

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