What should be the order of arrangement of de-Broglie wavelength of electron (λ?), an α – particle (λα) and proton (λ?) given that all have the same kinetic energy ?
What should be the order of arrangement of de-Broglie wavelength of electron (λ?), an α – particle (λα) and proton (λ?) given that all have the same kinetic energy ?
Option 1 -
λₑ = λₚ = λₐ
Option 2 -
λₑ < <
Option 3 -
λₑ = λₚ > λₐ
Option 4 -
λₑ > λₚ > λₐ
Asked by Shiksha User
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1 Answer
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Correct Option - 4
Detailed Solution:λ = h/mv = h/√2mK
For same K:
λ ∝ 1/√m
λ? : λ? : λ? = 1/√m? : 1/√m? : 1/√4m?
As m? > m? ,
λ? > λ? > λ?
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