What will be the most suitable combination of three resistors A = $2\Omega$ , B = $4\Omega$ , C = $6\Omega$ so that $\left(\frac{22}{3}\right)\Omega$ is equivalent resistance of combination

Correct Option - 2


Detailed Solution:

Given

$\begin{array}{l}A=2\Omega \\ B=4\Omega \\ C=6\Omega \\ R_{eq}=\frac{2\times 4}{2+4}+6\end{array}$

$R_{eq}=\frac{22}{3}\Omega$

<p>Given</p><div><div><picture><source srcset="" media=" (max-width: 500px)"><img src="https://images.shiksha.com/mediadata/images/1753177805php8y7MQ6.jpeg" alt="" width="152" height="90" loading="lazy"></picture></div></div><p><math><mtable columnalign="left"><mtr><mtd><mrow><mi>A</mi><mo>=</mo><mn>2</mn><mi>Ω</mi></mrow></mtd></mtr><mtr><mtd><mrow><mi>B</mi><mo>=</mo><mn>4</mn><mi>Ω</mi></mrow></mtd></mtr><mtr><mtd><mrow><mi>C</mi><mo>=</mo><mn>6</mn><mi>Ω</mi></mrow></mtd></mtr><mtr><mtd><mrow><msub><mrow><mi>R</mi></mrow><mrow><mi>e</mi><mi>q</mi></mrow></msub><mo>=</mo><mfrac><mrow><mn>2</mn><mo>×</mo><mn>4</mn></mrow><mrow><mn>2</mn><mo>+</mo><mn>4</mn></mrow></mfrac><mo>+</mo><mn>6</mn></mrow></mtd></mtr></mtable></math></p><p><math><mrow><msub><mrow><mi>R</mi></mrow><mrow><mi>e</mi><mi>q</mi></mrow></msub><mo>=</mo><mfrac><mrow><mn>2</mn><mn>2</mn></mrow><mrow><mn>3</mn></mrow></mfrac><mi>Ω</mi></mrow></math></p>

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