Write the value of current i₃ (in mA) in the circuit shown in the figure.

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alok kumar singh | Contributor-Level 10

2 months ago

$5 \times 1 0^{3} I_{1} = 60$

$\Rightarrow I_{1} = \frac{60}{5 \times 1 0^{3}} = 12 m A$

Potential difference across

$10 k Ω = 240 - 60 = 180 V$

$I_{2} = I_{3} - I_{1} = 6 m A$

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Write the value of current i₃ (in mA) in the circuit shown in the figure.

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Write the value of current i3 (in mA) in the circuit shown in the figure.

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Write the value of current i₃ (in mA) in the circuit shown in the figure.