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You are given that Mass of ?Li = 7.0160u, Mass of ?He = 4.0026u and ¹H = 1.0079u. When 20 g of ?Li is converted into ?He by proton capture, the energy liberated, (in kWh), is [Mass of nucleon = 1GeV/c²]

Option 1 -

4.5 * 10⁵

Option 2 -

8 * 10⁶

Option 3 -

6.82 * 10⁵

Option 4 -

1.33 * 10⁶

0 6 Views | Posted a month ago
Asked by Shiksha User

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Determine the number of nuclei that will be decayed upto one average life of radioactive material? (N0 : Initial number of nuclei)

 
A
alok kumar singh

N = N0e–λt

->t = λN = N0/e

So number of nuclei decayed = N0 – N

= N0 (1- 1/e) 

Density of nucleus is of the order of
A
alok kumar singh

Density of nuclei is order of 1017 kg m–3.

Power factor of series LCR circuit at resonance is
A
alok kumar singh

Kindly go through the solution '

 

Density of nucleus is of the order of
V
Vishal Baghel

Density of nuclei is order of 1017 kg m-3.

Two radioactive substances X and Y originally have N1 and N2 nuclei respectively. Half life of X is half of the life of Y. After three half lives of Y, number of nuclei of both are equal.

The ratio  N 1 N 2  will be equal to:
V
Vishal Baghel

Number of half lives of Y = 3

Number of half lives of X = 6 [As half life of X is half of that of Y].

N 1 2 6 = N 2 2 3 ⇒ N 1 N 2 = 8

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