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Direction of E is perpendicular to the direction of propagation and that of B.
E = cB = 3 × 10? × 2 × 10? = 6 V/m

Molality = (mole of solute * 1000) / wt of solvent (gm)
100 = (n_solute * 1000) / [ (1 - n_solute) * 18]
(1 - n_solute) / n_solute = 1000 / (100 * 18) = 10/18
18 (1 - n_solute) = 10 n_solute
18 - 18 n_solute = 10 n_solute
18 = 28 n_solute
n_solute = 18 / 28? 0.6428 = 64.28 * 10? ²
Ans = 64 (Rounded off)

Yes, the BA course offered at Harsha Institutions is a dual degree programme where candidates pursue both BA and BEd during their course. The course is taught with the objective of allowing students to pursue a career in teaching of various subjects in various fields such as language, social science, general Science and more. Candidates can learn more about the course by visiting the official website.

For n = 4, the possible values of l are 0, 1, 2, 3.
For l = 3, and m = -3.
Radial nodes = (n - l - 1) = (4 - 3 - 1) = 0
Ans = 0

Candidates who have passed Class 12 with Physics, Chemistry and Biology or any other examination with a minimum of 50% aggregate and also in PCB are eligible to apply for BPT at Jamia Hamdard University. The selection is also based on NEET-UG scores of the candidates.

Cr? O? ²? + Fe²? - (H? )-> Cr³? + Fe³?
(n=6) (n=1)
Meq Cr? O? ²? = Meq Fe²?
20 × 0.03 × 6 = 15 × M × 1
M = (20 × 0.03 × 6) / 15 = 0.24 = 24 × 10? ²
Ans = 24

Students comparing the BSc programme at Pt. Sundarlal Sharma (Open) University with other institutes, should consider tuition fees, curriculum, specialisations, faculty quality, and industry exposure. While the Pt. Sundarlal Sharma (Open) University BSc offers a highly affordable fee of INR 17,100 to INR 18,600, evaluating factors such as internships and overall return on investment ensures a well-thought-out decision.

Yes, candidates who wish to gain admissions into the BA courses at Harsha Institutions must clear ther Class 12 board exams with English as a mandatory subject and any one optional subject. The stream chosen by a candidate does not matter for Harsha Institutions BA admissions as long as English is a mandatory subject. The Class 12 board exam must also be cleared from a recognised board.

Magnetic field at centre of a solenoid is proportional to the current through it. Current through C will be one-third of the current through A. So
Magnetic field at the centre of C = 3/3 = 1T.

In a purely resistive AC circuit, if V = V? sin (ωt), then the current I is:
I = (V? / X? ) * sin (ωt - π/2)

P? + 3NaOH + 3H? O → PH? + 3NaH? PO? (A)
Here, NaH? PO? is a reducing agent.
NaH? PO? + AgNO? + H? O → Ag + HNO? + NaH? PO?
Equivalents of NaH? PO? = equivalents of Ag (n-factor of NaH? PO? = 4)
1 mole × 4 = n moles of Ag × 1
So, moles of Ag = 4.

Jamia Hamdard University offers MPharm for two-years at the PG level. The programme is spread across four semesters. Those who have passed BPharm with a minimum of 55% aggregate can apply for any of the below-mentioned MPharm specialisations:

• Pharmaceutics
• Pharmacology
• Pharmaceutical Chemistry
• Pharmacognosy
• Pharmacy Practice
• Pharmaceutical Quality Assurance
• Pharmaceutical Analysis
• Pharmaceutical Biotechnology

For the weak acid HA in the presence of strong acid HCl:
Ka = [ (Cα + 0.1) × Cα] / [C (1-α)] ≈ (0.1 × 10? ²α) / 10? ² = 0.1α
Given Ka = 2 × 10?
2 × 10? = 10? ¹ × α
α = 2 × 10?
Ans = 2

According to principle of equi-partition of Energy, the average energy per molecules associated with each degree of freedom is (1/2)kT.

Mole of CH? = 6.4 / 16 = 0.4 and mole of CO? = 8.8 / 44 = 0.2
Total mole = (0.4 + 0.2) = 0.6 mole of a non-reacting mixture of gas
Using Ideal Gas Law; P = nRT / V
P = (0.6 × 8.314 × 300) / 10 = 149.65 kPa
Ans = 150 (Rounded off)

Yes, Ashoka University also levies one-time admission and security deposits in BA total fees 2025. It generally range from INR 1 Lacs to INR 1.1 lakh. These are payable at the time of admission and are in addition to recurring examination form expenses etc.

Candidates who have passed Class 12 examination with Physics, Chemistry and Biology or Mathematics or any other examination with a minimum of 45% aggregate are eligible to apply for DPharm programme at Jamia Hamdard University. Also, the age of the aspirants must be 17 years on or before December 31, 2024 as per the PCI norms.

Harsha Institutions BA courses do not require candidates to clear any entrance exams. Admissions into Harsha Institutions are merit based where the scores of a candidate in their last qualifying exam are taken into consideration to determine whether they get admission into the BA courses or not. Candidates only need to clear their Class 12 board exams for a recognised board.

Kt = 2.303 log? (A? /A? )
K × 570 = 2.303 log? (100/32)
K = [2.303 / 570] [log?10² - log?2? ]
K = [2.303 / 570] [2 - 5 × 0.301] = [2.303 / 570] × 0.495 = 0.002 = 2.0 × 10? ³ s? ¹
Ans = 2