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5 months ago

0 Follower 10 Views

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Indrani Thakur

Contributor-Level 7

The details related to IBPS RRB exam centre are mentioned in the admit card. Candidates are required to reach the exam centre on time. Candidates reaching the exam centre late are not allowed to appear for the exam.

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5 months ago

0 Follower 5 Views

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Vishal Baghel

Contributor-Level 10

The force (F) exerted by radiation is the rate of change of momentum (p).
F = Δp/Δt
For photons, p = E/c. So, F = (1/c) * (ΔE/Δt).
Since Power (P) is ΔE/Δt, F = P/c.
Intensity (I) is Power per unit Area (P/A).
The formula provided in the document is F/A = (nE)/ (Δt c A) which leads to a final calculated value of 25 W/cm².

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5 months ago

0 Follower 2 Views

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Piyush Jain

Contributor-Level 10

The provision of direct admissions for BA courses at the University of Calcutta is not applicable. To get admissions into BA courses, applicants are required to complete the basic eligibility requirements and go through a selection process. However, the admission requirements and provision of direct admission can be different at affiliated colleges and institutions. For that, applicants must visit the official website of the particular institute.

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5 months ago

0 Follower 3 Views

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Vishal Baghel

Contributor-Level 10

The formula for escape velocity (v_e) is v_e = √ (2GM/R).
According to the question, the new escape velocity (v_e') from a new radius R' is related to the original escape velocity by 10v_e' = v_e.
10 * √ (2GM/R') = √ (2GM/R)
Squaring both sides:
100 * (2GM/R') = (2GM/R)
100/R' = 1/R
R' = R/100

If R is the radius of Earth (6400 km), then:
R' = 6400 km / 100 = 64 km

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5 months ago

0 Follower 8 Views

A
alok kumar singh

Contributor-Level 10

With decrease in inter-nuclear distance, the potential energy of the system decreases, reaches a minimum value and then sharply increases due to rise in inter-electronic as well as inter-nuclear repulsions

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5 months ago

0 Follower 3 Views

I
Indrani Tyagi

Contributor-Level 10

The total tuition fee for BA courses at Calcutta University ranges from INR 900 to INR 4.2 lakh. Apart from the tuition fee, there are several other components of total fees, such as hostel fees, admission fees, application fees, etc. The fee amount mentioned is sourced from the official website/sanctioning body and is subject to changeTherefore, it is indicative.

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5 months ago

0 Follower 4 Views

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Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

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5 months ago

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Nishtha Hazarika

Contributor-Level 10

Council of Education and Development Programmes application process can be completed either online or offline depending on students preference. For an offline application students can visit college's campus. Students can visit official website of Council of Education and Development Programmes and register. Once registered login using registered credentials and fill out application form. Submit duly filled-in form along with specified application fees to complete process.

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5 months ago

0 Follower 2 Views

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Mani Lama

Contributor-Level 7

A CRS score above 480 is considered competitive as of 2025. Note that, the minimum cut-off changes almost every draw. In some draws, the cut-off may be below 480, while in others it could be higher depending on the pool's competitiveness.

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5 months ago

0 Follower 16 Views

V
Vishal Baghel

Contributor-Level 10

The number of revolutions can be found using the rotational kinematic equation for angular displacement (θ):
θ = (ω_initial + ω_final)/2 * t
Number of revolutions = θ / 2π
Number of revolutions = [ (ω_final + ω_initial) * t] / (2 * 2π)

Based on the numerical values provided in the document, the calculation is:
Number of revolution = [ (2π × 3360/60 + 0) × t] / (2 * 2π) . with further calculation yielding the result:
Number of revolution = 728

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5 months ago

0 Follower 64 Views

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Piyush Bhandari

Contributor-Level 6

The SSC CHSL Tier 1 exam was not held in September 2025. The Staff Selection Commission conducted the exam in November 2025. The exam dates were November 12 to 30, 2025.

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5 months ago

0 Follower 2 Views

A
Aishwarya Malhotra

Contributor-Level 10

To get into the Council of Education and Development Programmes (CEDP), you can follow these steps:

  1. Online Application: Visit the official CEDP website and navigate to the admissions section. Here, you can fill out the online application form by providing the required personal and academic information.

  2. Merit-Based Selection: CEDP's admissions are conducted on a merit basis. Ensure that your academic records meet the eligibility criteria for the specific course you are interested in.

  3. Submission of Documents: Prepare and submit necessary documents such as academic transcripts, identification proof, and any other documents specified by the i

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5 months ago

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alok kumar singh

Contributor-Level 10

Among its different uses noradrenaline is used as an anti-depressant.

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5 months ago

0 Follower 5 Views

A
Abhishek Hazarika

Contributor-Level 10

Yes, Calcutta University does offer BA courses as general and honours courses for the duration of three years, divided into six semesters. The university offers BA courses through the affiliated colleges and its campus. To get admission into the courses, applicants are required to complete their Class 12 with relevant subjects.

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5 months ago

0 Follower 1 View

A
Aashi Tiwari

Contributor-Level 7

You can use the official IRCC CRS calculator available on the IRCC website. Also, there you can find tables of points for different factors. You'll need details about your age, education, work experience, language test scores, and other factors like job offers or nominations.

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5 months ago

0 Follower 2 Views

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Vishal Baghel

Contributor-Level 10

The equations for an object rolling down an inclined plane without slipping are:

·       Force equation: mg sinθ - f_s = ma

·       Torque equation: f_s R = Iα

Since a = αR, we can write f_s = Iα/R = Ia/R².
Substituting this into the force equation:
mg sinθ - Ia/R² = ma
mg sinθ = a (m + I/R²)
a = (mg sinθ) / (m + I/R²)

The time taken to travel a distance S is given by S = ½ at², which means t ∝ 1/√a. Therefore, the object with the largest acceleration (a) will arrive first.

The problem i

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5 months ago

0 Follower 5 Views

A
alok kumar singh

Contributor-Level 10

ρ = M/V
∴ 6.17 = (2 x MX? ) / (N? x (300 x 10? ¹? )³)
Solving MX? = 50 g
∴ No. of molecules in 200 g
= (200/50) x N? = 4 N?

New Question

5 months ago

0 Follower 4 Views

V
Virajita Kumari

Contributor-Level 7

The CRS is a points based system used by Canadian Government to rank Express Entry candidates for offering permanent residency. In short, your CRS score determines your place in the pool. The higher score means higher chance of receiving an Invitation to Apply (ITA) for PR.

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5 months ago

0 Follower 7 Views

V
Vishal Baghel

Contributor-Level 10

Initial charge Q = CV = 14 × 10? ¹² × 12 = 168 × 10? ¹² C

Initial energy U_in = ½ CV² = ½ (14 × 10? ¹²) × 12² = 1008 pJ

When the battery is disconnected and a dielectric (k=7) is inserted, the new capacitance is C' = kC.

The charge Q remains constant.

Final energy U_f = Q²/2C' = Q²/ (2kC) = (CV)²/ (2kC) = CV²/ (2k)

U_f = (14 × 10? ¹² × 12²) / (2 × 7) = 144 pJ

Mechanical energy available for oscillation

New Question

5 months ago

0 Follower 3 Views

M
Manashjyoti Srivastava

Contributor-Level 10

Council of Education and Development Programmes' admission process involves several steps, such as application, selection, and admission confirmation. Candidates wishing to apply for any of the offered programmes need to make sure that they satisfy the admission criteria of the desired course. Students are shortlisted based on academic merit secured in the last qualifying examination. The college may consider entrance exam scores if deemed necessary, depending on the course and its criteria. Selected students need to pay the Council of Education and Development Programmes admission fees for seat confirmation.

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