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New Question

10 months ago

0 Follower 1 View

H
Himanshu Singh

Contributor-Level 10

Yes, admissions at Srusti Academy of Management and Technology are currently open for the MBA. Prospective students can apply by visiting the official Srusti Academy website. It is recommended to check the website regularly for the latest updates on application deadlines and admission procedures.

New Question

10 months ago

0 Follower 1 View

S
Shikha Arora

Contributor-Level 10

The college offers courses in the field of Engineering, including B.E., B.Tech, M.E., M.Tech, and PhD. These courses are offered under the affiliation with Anna University. Admissions to all the courses are administered by the Directorate of Technical Education. SVCE admission is completely entrance-based. Students can check the table below to know course-wise eligibility:

Course Name

Eligibility

B.E./BTech

Class 12 with a 45% aggregate (40% for the reserve category) with Mathematics, Physics and Chemistry as subjects 

BTech (Lateral Entry)

Pass a 3-year Diploma in Mechanical/ Marine/ EEE/ ECE with a minimum of 55% in the final year

Obtained a minimum of 50% aggregate in English in Class 10 or Diploma

Medical fitness certificate & Merchant Marine Psychometric Evaluation Test certificate

M.E./MTech

UG degree in BTech from a recognised university

New Question

10 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

= 3 [ 0 ( 5 ) ( 1 ) ] + 1 ( 0 3 ( 1 ) 2 [ 0 × ( 5 ) 0 × 3 ]

= 15 + 3

= 12

=3 [1×1− (−2)×3]+4 [1×1− (−2)×2]+5 [3×1−2×1]

= 3 [1+6]+4 [1+4]+5 (3−2)

= 3×7+4×5+5×1

= 21+20+5

= 46

= 0 –1 [ − 1×0 – (−2)× (−3)] + 2 [−1×3 – (−2)×0]

= (− 1)× ( − 6)+2 (− 3)

= 6 – 6

= 0

= 2 [2×0− ( − 5)× (−1)]+3 [ (−1)× (− 1) – (− 2)×2]

= 2 (−5)+3 (1+4)

= 2 (−5) + 3× (5)

= −10+15

= 5

New Question

10 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

=3 [36 – 6×0]

= 108

RHS = 27. |A| = 27 4 = 108

∴ LHS = RHS

New Question

10 months ago

0 Follower 9 Views

V
Vishal Baghel

Contributor-Level 10

Given, A=  [1342]

So, 2A= 2  [1442]

[2484] .

L.H.S. = |2| = |2484| = 2×4 – 4×8 = 8−32 = −24

R.H.S. = 4 || = 4 |1242| = 4 (1×2 – 2×4)

= 4 [2 − 8]

= 4 [−6] = 24.

LHS = RHS

New Question

10 months ago

0 Follower 1 View

N
Nishtha Shukla

Guide-Level 15

BVCOE Mumbai offers a full-time BE programme for four-years at the UG level. The course is divided into eight semesters. Candidates who have completed HSc or its equivalent examination with relevant subjects are eligible to apply for any of the below-mentioned BE specialisations:

New Question

10 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

(i) |cosθsinθsinθcosθ|

=cosθ×cosθ (sinθ)×sinθ

= cos²θ + sin²θ

=1

(ii) |x2x+1x1x+1x+1|

= (x2x+1) (x+1) (x1) (x+1)

x3 + x2 − x2 − x + x +1 – x2  + 1

= x3x2 + 2

New Question

10 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

|2451|= 2× (−1) – 4× (−5) = −2+20 = 18

New Question

10 months ago

0 Follower 1 View

N
Nishtha Shukla

Guide-Level 15

Bharati Vidyapeeth College of Engineering students are open to scholarships offered by the state or central government. Students can apply for Rajarshi Chhatrapati Shahu Maharaj Shikshan Shulkh Shishyavrutti Yojna (EBC),  Scholarship for students of minority communities pursuing Higher and Professional courses (DTE),  Post Matric Scholarship to OBC Students,  Post Matric Scholarship to SBC Students,  Post Matric Scholarship to VJNT Students,  Government of India Post Matric Scholarship, etc. Students must fulfill the criteria to apply for a scholarship.

New Question

10 months ago

0 Follower 3 Views

A
abhishek gaurav

Contributor-Level 9

New Question

10 months ago

0 Follower 3 Views

A
abhishek gaurav

Contributor-Level 9

New Question

10 months ago

0 Follower 6 Views

R
Rashmi Shukla

Contributor-Level 10

DTU is situated in North-West Delhi, India. It is approximately 32 kilometers from the Indira Gandhi International Airport, New Delhi. From ISBT Kashmiri Gate/New Delhi Railway Station Use the Delhi Metro Rail Service to reach the Rithala Metro station. Once at Rithala, board local transport.

New Question

10 months ago

0 Follower 4 Views

A
abhishek gaurav

Contributor-Level 9

New Question

10 months ago

0 Follower 3 Views

A
abhishek gaurav

Contributor-Level 9

New Question

10 months ago

0 Follower 11 Views

N
Nishtha Gupta

Contributor-Level 8

Tezpur University offers BCom as a part of the Integrated BCom+ MCom course. The University offers this 5 year course with annual intake of 33 students. Admission to the respective course is offered on the basis of merit and accepted entrance exam. Therefore, candidates must secure a minimum aggregate of 60% in Class 12 and valid scores in exams such as CUET.

New Question

10 months ago

0 Follower 2 Views

L
Liyansha Jain

Contributor-Level 10

Candidates willing to get admission to various courses must apply online on the official website of DTU. At the undergraduate level, Delhi Technological University offers BTech, BDes, BA (Hons),  BBA, and other courses to students. At the postgraduate level, the university offers MBA, BDes,7  BDes,77 and various other courses to students. BTech is provided in around 15 specialisations such as Mechanical Engineering (ME), Production & Industrial Engineering (PIE), and others.

New Question

10 months ago

0 Follower 3 Views

New Question

10 months ago

0 Follower 4 Views

A
abhishek gaurav

Contributor-Level 9

New Question

10 months ago

0 Follower 8 Views

R
Rashmi Arora

Contributor-Level 10

Yes, admissions are open at DTU. Candidates willing to get admission to various courses must take part in the DTU admission process before the last date of admission. Candidates must know their DTU eligibility criteria and apply accordingly. Follow the DTU application process mentioned below:

Step 1: Visit the official website of Delhi Technological University.

Step 2: Select the course and pay the application fee.

Step 3: Fill out and submit the application form with the required information.

New Question

10 months ago

0 Follower 4 Views

L
Liyansha Gaurav

Contributor-Level 10

SVCE accepts CET exam scores for BTech and TANCET/CET scores for M.Tech course. Out of the 1,020 total seats for the BTech course, 50% are filled up through Tamil Nadu Government Department of Technical Education Online-counseling. To be noted is that the seats offered by SVCE are filled up within the first few days of counseling with significant-high cut-off marks. The remaining 50% seats are filled through management quota, as per the Govt. norms.

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