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New Question

5 months ago

0 Follower 2 Views

A
Ashwin Yadav

Contributor-Level 10

Students seeking Swami Shraddhanand College admissions must note that admission is conducted on the basis of entrance test. Students are required to appear for the CUET test, which is held by the NTA for DU admissions. Hence, as such there is no provision for direct admission at Swami Shraddhanand College Delhi University. Candidates can specify their college preferences during the application process and complete the joining formalities at the college campus.

New Question

5 months ago

0 Follower 1 View

A
Ashwin Yadav

Contributor-Level 10

Swami Shraddhanand College admissions are conducted on the basis of the prescribed entrance exam. Students seeking admission must clear their previous qualifying examination (10+2/UG), and appear for the Common University Entrance Exam (CUET). Students can appear for the CUET exam and exercise their choice of college. Students can visit the official website to learn more.

New Question

5 months ago

0 Follower 2 Views

M
Meitankeisangbam Vasundhara devi

Contributor-Level 10

A slightly fluctuating trend has been observed while analysing the placement details recorded at College of Engineering, Bharati Vidyapeeth. For further trend analysis, check out the table below:

Particulars

Placement Statistics (2022)

Placement Statistics (2023)

Placement Statistics (2024)

the highest Package

INR 12.6 LPA

INR 27 LPA

INR 19 LPA

Average Package

INR 6.5 LPA

INR 7.8 LPA

INR 5.15 LPA

the lowest Package

INR 3.25 LPA

INR 3.5 LPA

INR 3.3 LPA

Placement Rate

90%

95%

85%

Companies Visited

68

65

65

New Question

5 months ago

0 Follower 5 Views

V
Vishal Baghel

Contributor-Level 10

This is a binomial probability problem with n=5. Let p be the probability of success and q be the probability of failure.
Given P (X=1) =? C? p¹q? = 5pq? = 0.4096 — (I)
Given P (X=2) =? C? p²q³ = 10p²q³ = 0.2048 — (II)
Divide (I) by (II): (5pq? ) / (10p²q³) = 0.4096 / 0.2048 = 2.
(1/2) * (q/p) = 2 ⇒ q/p = 4 ⇒ q = 4p.
Using p+q=1, we have p+4p=1 ⇒ 5p=1 ⇒ p=1/5.
And q = 4/5.
We need to find P (X=3) =? C? p³q².
P (X=3) = 10 * (1/5)³ * (4/5)² = 10 * (1/125) * (16/25) = 160 / 3125 = 32 / 625.

New Question

5 months ago

0 Follower 2 Views

A
Ashwin Yadav

Contributor-Level 10

Swami Shraddhanand College DU admissions are conducted on the basis of entrance test, and the accepted exam is CUET/CUET-PG. Students can follow the below provided steps:

  1. Visit the website of NTA CUET and register for the test.
  2. Appear for the exam and obtain valid merit for desired college.
  3. Pay the application fees and complete the joining formalities at Swami Shraddhanand College.

New Question

5 months ago

0 Follower 1 View

N
Nishtha Hazarika

Contributor-Level 10

No, Government College of Engineering, Ratnagiri admissions are not merit-based. The college admits students based on scores obtained in the state-level common entrance test (MHTCET) conducted by the concerned body. Hence, Government College of Engineering, Ratnagiri admissions are entrance-based instead. Further, seat allocation is via the Centralised Admission Process (CAP) rounds. 

New Question

5 months ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

The following depicts a chemical reaction leading to a Major Product Y.
Mercury has low boiling point so is refined by distillation method.
Copper refining is done through electrolytic refining.
Silicon is refined by zone refining method.
Nickel is refined by vapour phase refining.

New Question

5 months ago

0 Follower 1 View

M
Meitankeisangbam Vasundhara devi

Contributor-Level 10

The average packages offered during the College of Engineering, Bharati Vidyapeeth placements 2022-2024 are presented below:

Particulars

Placement Statistics (2022)

Placement Statistics (2023)

Placement Statistics (2024)

Average Package

INR 6.5 LPA

INR 7.8 LPA

INR 5.15 LPA

New Question

5 months ago

0 Follower 1 View

M
Meitankeisangbam Vasundhara devi

Contributor-Level 10

The list of top recruiters during College of Engineering, Bharati Vidyapeeth placements are presented below:

College of Engineering, Bharati Vidyapeeth Top Recruiters

Amazon

Emirates 

Capgemini

HSBC

Honda

MU Sigma 

Siemens

Toshiba 

PhonePe

New Question

5 months ago

0 Follower 2 Views

A
Ashwin Yadav

Contributor-Level 10

Swami Shraddhanand College DU offers the flagship programmes of BSc, BA, and BCom to students seeking UG admissions. These courses are available in a diverse variety of spcecialisations. Candidates looking for PG admissions can opt for different programmes such as MA and MSc. Students can visit the official website of Swami Shraddhanand College to learn more about courses and specialisations.

New Question

5 months ago

0 Follower 7 Views

New Question

5 months ago

0 Follower 2 Views

A
Ashwin Yadav

Contributor-Level 10

Swami Shraddhanand College is a popular DU college located in Alipur, Delhi. The institute is duly recognised by the UGC and provides courses in Science, Humanities, and Commerce. Popular programs include BSc, BA, MSc, etc. The college has a state-of-the-art infrastructure and students experience all-round development with various events and fests.

New Question

5 months ago

0 Follower 7 Views

New Question

5 months ago

0 Follower 12 Views

R
Raj Pandey

Contributor-Level 9

Please consider the following Image

 

New Question

5 months ago

0 Follower 1 View

A
Aishwarya Malhotra

Contributor-Level 10

Government College of Engineering, Ratnagiri eligibility criteria require candidates to pass the last qualifying examination. As the college offers courses at the undergraduate level, students must pass Class 12 with relevant subjects and the specified aggregate. To be eligible for Government College of Engineering, Ratnagiri admissions, students must also secure a valid score in the state-level common entrance test. For more details, candidates can visit the official website of the college.

New Question

5 months ago

0 Follower 9 Views

H
heau mishr

Contributor-Level 10

PES University admission for UG and PG courses are entrance based. Candidates are shortlisted for the interview after PESSAT. Shortlisting is done on the basis of merit with reference to the PESSAT scores of the candidates. Hereafter, the list of candidates who qualify PESSAT is notified on the official website and the interview round commences for the shortlisted candidates.

New Question

5 months ago

0 Follower 2 Views

New Question

5 months ago

0 Follower 3 Views

P
Piyush Rastogi

Contributor-Level 9

Trine University offers 2 MS courses to international students, which are MS Information Studies and Master of Science in Business Analytics, which are 18 months long with the first-year fee of INR 9 L. Both of these programs require 30 credit hours.

Below are the Trine University MS admission requirements:

  • Transcripts of the degree
  • Bachelor's degree with a minimum of 2.5 on a scale of 4.0
  • Must meet the English requirements
  • Letters of recommendation
  • SOP
  • Resume/CV
  • Standardized test scores, such as the GMAT, for some programs
  • Some programs might have additional requirements, depending on the course.
  • English Language Proficiency

New Question

5 months ago

0 Follower 6 Views

K
Kartik Bisht

Contributor-Level 10

Yes, IELTS is required at Deakin University for international students. International students whose native language is not English, are required to submit proof of English proficiency at Deakin. The university accept various English language test such as PTE, TOEFL, and more. International students must attain the minimum English language score at Deakin University that are listed below:

English Proficiency Test

BAND A

BAND B

BAND C

BAND D

IELTS

Overall 6.0 with a minimum of 6.0

Overall 6.5 with a minimum of 6.0

Overall 7.0 with a minimum of 6.5

Overall 7.0 with a minimum of 7.0

PTE

Overall 50 with a minimum of 50 in each skill

Overall 58 with a minimum of 50 in each skill

Overall 65 with a minimum of 58 in each skill

Overall 65 with a minimum of 65 in each skill

TOEFL

69

79

94

94

New Question

5 months ago

0 Follower 9 Views

V
Vishal Baghel

Contributor-Level 10

We are given bounds for a function f (t) on two intervals and need to find the range of g (3) = ∫? ³ f (t) dt.
We split the integral: g (3) = ∫? ¹ f (t)dt + ∫? ³ f (t)dt.
For the first interval t ∈ [0, 1], we have 1/3 ≤ f (t) ≤ 1. Integrating from 0 to 1 gives:
∫? ¹ (1/3) dt ≤ ∫? ¹ f (t)dt ≤ ∫? ¹ 1 dt ⇒ 1/3 ≤ ∫? ¹ f (t)dt ≤ 1.
For the second interval t ∈ (1, 3], we have 0 ≤ f (t) ≤ 1/2. Integrating from 1 to 3 gives:
∫? ³ 0 dt ≤ ∫? ³ f (t)dt ≤ ∫? ³ (1/2) dt ⇒ 0 ≤ ∫? ³ f (t)dt ≤ (1/2) (3

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