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5 months agoContributor-Level 10
For a UK Skilled Worker visa, the minimum IELTS score required is usually 4.0 in all four sections: reading, writing, speaking, and listening. This requirement can vary depending on the type of job and visa category, so students must check the latest UK government guidelines.
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5 months agoContributor-Level 9
An MBA is offered at Trine University, which typically lasts from 18 to 24 months. The MBA program offered at this university is accredited by the Accreditation Council for Business Schools and Programs (ACBSP).
Below are the Trine University MBA admission requirements:
- A Bachelor's degree with a 3.0 GPA on a scale of 4.0
- Application form
- English proficiency test scores (TOEFL, IELTS, PTE)
- Official transcripts
- Two Letters of Recommendation
- GMAT
- Essays about the goals of the applicant
- Updated resume
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5 months agoContributor-Level 10
During the College of Engineering, Bharati Vidyapeeth placement drive 2024, 85% of students secured placements in top companies. Check out the key highlights of College of Engineering, Bharati Vidyapeeth placements 2024 as compared with 2023 and 2022 presented below:
Particulars | Placement Statistics (2022) | Placement Statistics (2023) | Placement Statistics (2024) |
|---|---|---|---|
the highest Package | INR 12.6 LPA | INR 27 LPA | INR 19 LPA |
Average Package | INR 6.5 LPA | INR 7.8 LPA | INR 5.15 LPA |
the lowest Package | INR 3.25 LPA | INR 3.5 LPA | INR 3.3 LPA |
Placement Rate | 90% | 95% | 85% |
Companies Visited | 68 | 65 | 65 |
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5 months ago
Contributor-Level 9
During nitration of aniline, meta- nitroaniline is also formed as product due to formation of –NH? group. The percentage of p, m and o product is 51%, 47% and 2% respectively
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5 months agoContributor-Level 10
Yes, an IELTS score of 6.0 is considered a decent score for studying in the UK. Many UK universities accept 6.0 bands for both undergraduate and postgraduate programs. However, some top-ranked universities may ask for 6.5 or higher depending on the course.
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5 months agoContributor-Level 10
For a system of linear homogeneous equations to have a non-trivial solution, the determinant of the coefficient matrix must be zero.
Δ = | 4 λ 2 |
| 2 -1 | = 0
| μ 2 3 |
To simplify, perform the row operation R? → R? - 2R? :
Δ = | 0 λ+2 0 |
| 2 -1 | = 0
| μ 2 3 |
Expand the determinant along the first row:
- (λ+2) * det (| 2 1 |, | μ 3 |) = 0.
- (λ+2) (2*3 - 1*μ) = 0.
(λ+2) (μ-6) = 0.
This implies that either λ+2 = 0 or μ-6 = 0.
So, the conditions are λ = -2 (for any μ) or μ = 6 (for any λ).
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5 months agoContributor-Level 10
KCET cut off for PES University BSc programme, year 2025 is as follows:
- General: 2,641-1.28,600
- OBC: 2,641-1,28,600
- SC: 30,341-1,55,074
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5 months agoContributor-Level 10
The general term Tr+1 in the expansion of (a/x + x)^n (assuming from context, as it is not explicitly stated) is:
Tr+1 = nCr * (a/x)^r * x^ (n-r) = nCr * a^r * x^ (n-2r)
(The text shows (a/x^2) leading to x^ (n-3r)
Assuming the term is (x + a/x^2)^n:
Tr+1 = nCr * x^ (n-r) * (a/x^2)^r = nCr * a^r * x^ (n-3r)
T3 = T (2+1) = nC2 * a^2 * x^ (n-6)
T4 = T (3+1) = nC3 * a^3 * x^ (n-9)
T5 = T (4+1) = nC4 * a^4 * x^ (n-12)
The ratio of the coefficients is given:
(nC2 * a^2) / (nC3 * a^3) = 12/8 = 3/2
(n (n-1)/2) * a^2) / (n (n-1) (n-2)/6) * a^3) = 3/2
(3 / (n-2) * (1/a) = 3/2 => a (n-2) = 2 (i)
(nC3 * a^3) / (nC4 * a^4) = 8/3
(n (n-1) (n-2)/6) * a^3)
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5 months agoContributor-Level 10
Yes, an overall IELTS score of 5.5 is accepted in many UK universities for foundation, diploma, or selected undergraduate and postgraduate programs. Some universities may also offer pre-sessional English courses along with the main course for students with IELTS 5.5.
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5 months agoContributor-Level 10
Many UK universities accept low IELTS scores, especially for foundation or pathway programs. Some of them are the University of East Anglia (UEA), University of Dundee, University of Sussex, and University of Liverpool. These universities accept an overall IELTS score of 5.5 for selected courses.
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5 months agoContributor-Level 10
The equation of the tangent to the ellipse x²/27 + y² = 1 at the point (3√3 cosθ, sinθ) is:
x (3√3 cosθ)/27 + y (sinθ)/1 = 1 ⇒ x/ (3√3) cosθ + y sinθ = 1.
To find the intercepts on the axes:
x-intercept (set y=0): x = 3√3 / cosθ = 3√3 secθ.
y-intercept (set x=0): y = 1 / sinθ = cosecθ.
The sum of the intercepts is z (θ) = 3√3 secθ + cosecθ.
To find the minimum value of z, we differentiate with respect to θ and set it to zero:
dz/dθ = 3√3 secθ tanθ - cosecθ cotθ = 0.
3√3
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5 months agoContributor-Level 10
The placements at BVCOE placement provides good opportunities to students for career growth. Every seasons top companies would visit the campus for placement drives. For more information, check out the table that presents the College of Engineering, Bharati Vidyapeeth placements for seasons 2022-2024:
Particulars | Placement Statistics (2022) | Placement Statistics (2023) | Placement Statistics (2024) |
|---|---|---|---|
the highest Package | INR 12.6 LPA | INR 27 LPA | INR 19 LPA |
Average Package | INR 6.5 LPA | INR 7.8 LPA | INR 5.15 LPA |
the lowest Package | INR 3.25 LPA | INR 3.5 LPA | INR 3.3 LPA |
Placement Rate | 90% | 95% | 85% |
Companies Visited | 68 | 65 | 65 |
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5 months agoContributor-Level 9
In Hoffmann bromamide reaction, hypobromite ion react with amide and in this reaction carbonyl group is lost as CO? ²? in form of Na? CO?
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5 months agoContributor-Level 10
To find the values of a and b, we evaluate the left-hand limit (LHL) and right-hand limit (RHL) at x=0 and equate them.
LHL: lim (x→0) sin (a+3)/2 * x / x = (a+3)/2. The full limit evaluates to (a+3)/2. So, (a+3)/2 = b.
This gives the relation a - 2b + 3 = 0 — (I)
RHL: lim (x→0) [√ (x+bx³) - √x] / (bx²).
Rationalize the numerator:
lim (x→0) [ (x+bx³) - x] / [bx² (√ (x+bx³) + √x)]
= lim (x→0) bx³ / [bx² (√x (√ (1+bx²) + √x)]
= lim (x→0) x / [√x (√ (1+bx²) + 1)] = lim (x→0) √x / (√ (1+bx²) + 1)
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5 months agoContributor-Level 10
The BVCOE is known for the good placements offered to its graduating students. Check out the placement details for the College of Engineering, Bharati Vidyapeeth placements 2022-2024 presented below:
Particulars | Placement Statistics (2022) | Placement Statistics (2023) | Placement Statistics (2024) |
|---|---|---|---|
the highest Package | INR 12.6 LPA | INR 27 LPA | INR 19 LPA |
Average Package | INR 6.5 LPA | INR 7.8 LPA | INR 5.15 LPA |
the lowest Package | INR 3.25 LPA | INR 3.5 LPA | INR 3.3 LPA |
Placement Rate | 90% | 95% | 85% |
Companies Visited | 68 | 65 | 65 |
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5 months agoContributor-Level 10
The problem provides non-standard formulas for sums S? and S? :
S? = n [a + (2n-1)d]
S? = 2n [a + (4n-1)d]
We are given S? - S? = 1000.
S? - S? = 2n [a + (4n-1)d] - n [a + (2n-1)d]
= (2na + 8n²d - 2nd) - (na + 2n²d - nd)
= na + 6n²d - and = n [a + (6n-1)d].
So, n [a + (6n-1)d] = 1000.
We need to find S? n. Assuming the pattern S? n = kn [a + (2kn-1)d], then S? n would be 3n [a + (6n-1)d].
S? n = 3 * (n [a + (6n-1)d]) = 3 * 1000 = 3000.
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5 months agoContributor-Level 10
Let X1, ., X2n be the first 2n observations and Y1, ., Yn be the last n observations.
Given:
ΣXi / 2n = 6 => ΣXi = 12n (i)
ΣYi / n = 3 => ΣYi = 3n (ii)
Combined mean: (ΣXi + ΣYi) / 3n = 5 => ΣXi + ΣYi = 15n. This is consistent with (i) and (ii).
Combined variance: (ΣXi^2 + ΣYi^2) / 3n - (mean)^2 = 4
(ΣXi^2 + ΣYi^2) / 3n - 5^2 = 4
ΣXi^2 + ΣYi^2 = (4 + 25) * 3n = 87n.
New observations are Xi + 1 and Yi - 1.
New mean = (Σ (Xi + 1) + Σ (Yi - 1) / 3n = (ΣXi + 2n + ΣYi - n) / 3n = (15n + n) / 3n = 16n / 3n = 16/3.
New variance k:
k = (Σ (X
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5 months agoContributor-Level 10
At PES University, the minimum eligibility varies with courses. However, the common eligibility for UG programmes is passing Class 12 with atleast 50 % of aggregate marks. For PG programmes at the university, the minimum eligibility is Bachelor's degree with atleast 50% of aggregate marks in the relevant stream. The sleection criteria for both the programmes is entrance based.
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