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The total fee structure for the BTech course might include multiple components, such as a tuition fee, a one-time fee, etc. Some of the fee components are required to be paid annually, semesterly or one-time. Check out the table below to know the exact fee structure of the BTech course at CIET Chandigarh:

No, the MCA course fee does not include cost of any textbooks or any other study material unless mentioned in the fee structure handed to you at the time of your MCA admission. Though when it comes to online MCA, generally, the digital study material is provided to you by the mentors. In case of an offline MCA, you may need to invest in physical study materials like books, sample papers, and additional software, considering MCA covers fundamental and advanced-level computer Science concepts.

For MA admissions in India, you'll need to have a bachelor's degree in a relevant discipline from a recognised university; that's the one prime condition. After this, there are percentage-related requirements, which can vary depending on the colleges. Also, there can be 5% relaxation for other categories like SC/ST/OBC. Moreover, most colleges accept or conduct entrance exams for MA-level courses. 

The Uttar Pradesh University of Medical Sciences may provide lateral entry to the BPharm course. Candidates who get selected are directly admitted to the second year of the programme. The aspirants wanting to take lateral entry may require a valid Diploma or the certificate as per the requirement of the university. 

Yes, CIET Chandigarh does offer scholarships to BTech students after completing certain eligibility requirements. Moreover, the institute also offers government-aided scholarships. Check out some of the offered scholarships:

First, the specific conductance (κ) is calculated (κ = conductance × cell constant), and units are converted. Then, the molar conductivity (Λ? ) is found using the formula Λ? = κ / Concentration, with all units in the SI system. The calculation yields 14.3 mS m² mol? ¹.
Answer: 14 (Rounded off)

There is a medical test in the AFCAT selection process. The medical test is conducted at the time of AFSB Interview. It is one of the most important factors in the selection process of AFCAT. Candidates not clearing the medical test are rejected from further processes.

The energy is calculated using the formula Δ? = hc/λ. Plugging in the values for Planck's constant (h), the speed of light (c), and the given wavelength gives an energy of 3.99 × 10? ¹? J. The answer is requested as a single digit.
Answer: 4 (in units of 10? ¹? J)

Using Raoult's Law, P_Total = P°_A·X_A + P°_B·X_B = (21 kPa × 1/3) + (18 kPa × 2/3) = 7 + 12 = 19 kPa.
Answer: 19 kPa

The reaction is Fe (s) + 2HCl (aq) → FeCl? (aq) + H? (g). 50 g of Fe corresponds to 0.89 moles, which produces 0.89 moles of H? (g). The work done by the gas is calculated using W = -Δn_gasRT. The work done by the gas is the positive value, 2218 J.
Answer: 2218 J

The partial pressure of dry N? is 758 - 14 = 744 mm Hg. Using the ideal gas law (PV=nRT), the moles of N? are calculated to be 1.25 × 10? ³ mol. This corresponds to 0.035 g of N? The percentage of nitrogen in the sample is (0.035 g / 0.1840 g) × 100, which is 18.96%.
Answer: 19 (Rounded)

This is a limiting reactant problem. The initial moles are 5.25 mmol of Pb (NO? )? and 2.4 mmol of Cr? (SO? )? Based on the 3:1 stoichiometric ratio, Pb (NO? )? is the limiting reactant. The moles of PbSO? formed are equal to the initial moles of the limiting reactant, which is 5.25 mmol or 5.25 × 10? ³ moles. The question asks for the answer in units of 10? moles.

Uttar Pradesh University of Medical Sciences BPharm selection is done based on applicants scores in the Combined Pharmacy and Nursing Entrance Test (CPNET). Candidates who pass the exam and secure a valid score are selected and seats are allotted through counselling. To be eligible for the programme, the aspirants must be Class 12 or equivalent examination pass from a recognised board. 

First, the number of unit cells in the given mass is determined. In an HCP structure, there are 6 atoms and 18 total voids (6 octahedral + 12 tetrahedral) per unit cell. Multiplying the number of unit cells by 18 gives the total number of voids. The result is14.9 x 10²¹, which is rounded.

Using the integrated rate laws for both reactions and solving for time 't' yields a value of 108.

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At Government College of Engineering, Ratnagiri, students are offered multiple BTech courses. The admission criteria is generally the same across all of the offered specialisations. Students must fulfil the same to get a seat at the college. Find below a list of BTech specialisations offered by the college:

• AI & Data Science
• Electrical Engineering
• Food Technology
• Mechatronics Engineering
• Civil Engineering

AFCAT selection process is the same for men and women candidates. The criteria in terms of height and weight is different from the male. Candidates applying for the AFCAT exam are required to appear for the online test and AFSB interview.