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The complex CoCl? ·4NH? is represented as [CoCl? (NH? )? ]Cl.
Here, 4 NH? are neutral monodentate ligands. So, 2 equivalents of ethylene diamine replace 4NH? since ethylene diamine is a didentate ligand.

ΔG° = -9.478 kJ/mol
Using ΔG° = -2.303 RT log K_p
-9.478 × 10³ = -2.303 × 8.314 × 495 log K_p
1 = log K_p ⇒ K_p = 10
Here, for the given reaction A (g)? B (g), K_p = K_c
Initial A = 22 mmol
At equilibrium A = 22 - x mmol; B = x mmol
K_c = [B] / [A] = (x/V) / (22-x)/V) = x / (22-x) = 10
x = 10 (22-x) ⇒ x = 220 - 10x ⇒ 11x = 220 ⇒ x = 20
So, mmol of B at equilibrium are 20.

m = 10 molal
K_b = 0.5 K kg mol? ¹
Using: ΔT_b = I K_b m
and α = (i - 1) / (n - 1)
n for AB? is 3; α = 0.1
0.1 = (i - 1) / (3 - 1) ⇒ I = 1.2
ΔT_b = 1.2 × 0.5 × 10 = 6 °C
So, boiling point of solution = 100 + 6 = 106 °C

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A 6.5 molal solution means 6.5 moles of KOH is in 1 kg (1000 g) of solvent (H? O).
Moles of solute, n_B = 6.5
Mass of solute, W_B = 6.5 × 56 = 364 g
Mass of solvent, W_A = 1000 g
Mass of solution = 1364 g
Volume of solution = 1364 / 1.89 mL
Now, molarity = [6.5 / (1364 / 1.89)] × 1000 M = 9 M

Moles of carbon in organic compound = Moles of carbon in CO?
n_c = 420 / 44 moles
Mass of carbon in organic compound = (420 / 44) × 12 = 114.54 g
Moles of hydrogen in compound = 2 × moles of H? O
n_H = 2 × (210 / 18) moles
Mass of hydrogen = 2 × (210 / 18) g = 23.33 g
% of H = (23.33 / 750) × 100 = 3.11%
The nearest integer is 3.

Solubility product of A? X = 4S? ³
Where S? is the solubility of salt A? X.
Solubility product of MX = S? ²
Where S? is the solubility of MX.
Given 4S? ³ = 4 × 10? ¹² ⇒ S? = 10? M
Given S? ² = 4 × 10? ¹² ⇒ S? = 2 × 10? M
So, S? / S? = 10? / (2 × 10? ) = 50

The balanced equation is:
2MnO? + 5C? O? ²? + 16H? → 2Mn²? + 10CO? + 8H? O
So, the value of c (coefficient for H? ) = 16.

Edge length in bcc, a? = 27 Å
Let, Edge length in fcc be a? Å
Now, the same element crystallises in bcc as well as fcc.
For bcc: 4r = √3 a? ⇒ r = (√3 / 4) a?
For fcc: 4r = √2 a? ⇒ r = a? / (2√2)
So, (√3 / 4) a? = a? / (2√2)
(√3 / 4) × 27 = a? / (2√2)
a? = 33.13 Å
The nearest integer is 33.

Antihistamines are antacids and antiallergics

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H? O? can act as both an oxidizing & reducing agent in both acidic & basic medium. In the hydrogen economy, energy is stored & transmitted in the form of dihydrogen.

Roasting is a process in which sulphur is removed as SO? gas from sulphide ores on heating in excess of oxygen.

Bismuth (Bi) is a metal in group 15. Its hydride is BiH? , which is the strongest reducing agent due to its the lowest thermal stability.

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Hydrated halides of group 2 from Ca onwards undergo dehydration on heating. But the hydrated halide of Mg, i.e., MgCl? ·8H? O, does not undergo dehydration on heating but undergoes hydrolysis.
BeO is amphoteric, while other oxides of group 2 are basic in nature.